Base | Representation |
---|---|
bin | 10011000110111100000… |
… | …100011101011011111001 |
3 | 11122112101121112022101211 |
4 | 103012330010131123321 |
5 | 133003232244423113 |
6 | 2443123353243121 |
7 | 163604226324136 |
oct | 23067404353371 |
9 | 4575347468354 |
10 | 1313120311033 |
11 | 466989201053 |
12 | 1925a94034a1 |
13 | 96a993a17ab |
14 | 477abcb158d |
15 | 24255bdeb3d |
hex | 131bc11d6f9 |
1313120311033 has 2 divisors, whose sum is σ = 1313120311034. Its totient is φ = 1313120311032.
The previous prime is 1313120311021. The next prime is 1313120311057. The reversal of 1313120311033 is 3301130213131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1271274290064 + 41846020969 = 1127508^2 + 204563^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313120311033 - 229 = 1312583440121 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313120310995 and 1313120311013.
It is not a weakly prime, because it can be changed into another prime (1313120311933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656560155516 + 656560155517.
It is an arithmetic number, because the mean of its divisors is an integer number (656560155517).
Almost surely, 21313120311033 is an apocalyptic number.
It is an amenable number.
1313120311033 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313120311033 is an equidigital number, since it uses as much as digits as its factorization.
1313120311033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 486, while the sum is 22.
Adding to 1313120311033 its reverse (3301130213131), we get a palindrome (4614250524164).
The spelling of 1313120311033 in words is "one trillion, three hundred thirteen billion, one hundred twenty million, three hundred eleven thousand, thirty-three".
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