Base | Representation |
---|---|
bin | 1011111100010101100100… |
… | …0110111010111000101111 |
3 | 1201111022221121021122210101 |
4 | 2333011121012322320233 |
5 | 3210120204230311114 |
6 | 43532221122251531 |
7 | 2523461424315223 |
oct | 277053106727057 |
9 | 51438847248711 |
10 | 13131210010159 |
11 | 4202a077a241a |
12 | 1580abb7b6ba7 |
13 | 74336344a797 |
14 | 3357a80a8783 |
15 | 17b88d861d74 |
hex | bf1591bae2f |
13131210010159 has 2 divisors, whose sum is σ = 13131210010160. Its totient is φ = 13131210010158.
The previous prime is 13131210010109. The next prime is 13131210010229. The reversal of 13131210010159 is 95101001213131.
It is a weak prime.
It is an emirp because it is prime and its reverse (95101001213131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13131210010159 - 229 = 13130673139247 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131210010109) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565605005079 + 6565605005080.
It is an arithmetic number, because the mean of its divisors is an integer number (6565605005080).
Almost surely, 213131210010159 is an apocalyptic number.
13131210010159 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131210010159 is an equidigital number, since it uses as much as digits as its factorization.
13131210010159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 810, while the sum is 28.
The spelling of 13131210010159 in words is "thirteen trillion, one hundred thirty-one billion, two hundred ten million, ten thousand, one hundred fifty-nine".
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