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1313121031231 is a prime number
BaseRepresentation
bin10011000110111100000…
…111001101010000111111
311122112101122212220022211
4103012330013031100333
5133003232440444411
62443123420521251
7163604235413632
oct23067407152077
94575348786284
101313121031231
11466989653159
121925a96b0227
1396a99594549
14477ac01bc19
1524255cd3221
hex131bc1cd43f

1313121031231 has 2 divisors, whose sum is σ = 1313121031232. Its totient is φ = 1313121031230.

The previous prime is 1313121031213. The next prime is 1313121031241. The reversal of 1313121031231 is 1321301213131.

Together with previous prime (1313121031213) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is an emirp because it is prime and its reverse (1321301213131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1313121031231 - 211 = 1313121029183 is a prime.

It is a super-2 number, since 2×13131210312312 (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313121031241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656560515615 + 656560515616.

It is an arithmetic number, because the mean of its divisors is an integer number (656560515616).

Almost surely, 21313121031231 is an apocalyptic number.

1313121031231 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313121031231 is an equidigital number, since it uses as much as digits as its factorization.

1313121031231 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 1313121031231 its reverse (1321301213131), we get a palindrome (2634422244362).

The spelling of 1313121031231 in words is "one trillion, three hundred thirteen billion, one hundred twenty-one million, thirty-one thousand, two hundred thirty-one".