Base | Representation |
---|---|
bin | 11000011101010111… |
… | …00110010011011001 |
3 | 1020220010200200110221 |
4 | 30032223212103121 |
5 | 203343042240433 |
6 | 10010555240041 |
7 | 643255313614 |
oct | 141653462331 |
9 | 36803620427 |
10 | 13131211993 |
11 | 5629254a19 |
12 | 2665749021 |
13 | 1313623033 |
14 | 8c7d6317b |
15 | 51cc1e72d |
hex | 30eae64d9 |
13131211993 has 2 divisors, whose sum is σ = 13131211994. Its totient is φ = 13131211992.
The previous prime is 13131211979. The next prime is 13131212033. The reversal of 13131211993 is 39911213131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13098344704 + 32867289 = 114448^2 + 5733^2 .
It is a cyclic number.
It is not a de Polignac number, because 13131211993 - 233 = 4541277401 is a prime.
It is not a weakly prime, because it can be changed into another prime (13131211693) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565605996 + 6565605997.
It is an arithmetic number, because the mean of its divisors is an integer number (6565605997).
Almost surely, 213131211993 is an apocalyptic number.
It is an amenable number.
13131211993 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131211993 is an equidigital number, since it uses as much as digits as its factorization.
13131211993 is an evil number, because the sum of its binary digits is even.
The product of its digits is 4374, while the sum is 34.
The spelling of 13131211993 in words is "thirteen billion, one hundred thirty-one million, two hundred eleven thousand, nine hundred ninety-three".
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