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13131222223187 is a prime number
BaseRepresentation
bin1011111100010101100111…
…0101100000100101010011
31201111022222110021010220202
42333011121311200211103
53210120220342120222
643532222240125415
72523461633162555
oct277053165404523
951438873233822
1013131222223187
114202a13684232
121580b0390686b
13743365b35723
143357a99674d5
1517b88e975892
hexbf159d60953

13131222223187 has 2 divisors, whose sum is σ = 13131222223188. Its totient is φ = 13131222223186.

The previous prime is 13131222223103. The next prime is 13131222223253. The reversal of 13131222223187 is 78132222213131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13131222223187 - 210 = 13131222222163 is a prime.

It is a super-4 number, since 4×131312222231874 (a number of 54 digits) contains 4444 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13131222223187.

It is not a weakly prime, because it can be changed into another prime (13131225223187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565611111593 + 6565611111594.

It is an arithmetic number, because the mean of its divisors is an integer number (6565611111594).

Almost surely, 213131222223187 is an apocalyptic number.

13131222223187 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131222223187 is an equidigital number, since it uses as much as digits as its factorization.

13131222223187 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 48384, while the sum is 38.

The spelling of 13131222223187 in words is "thirteen trillion, one hundred thirty-one billion, two hundred twenty-two million, two hundred twenty-three thousand, one hundred eighty-seven".