Base | Representation |
---|---|
bin | 1011111100010101101001… |
… | …0011111100100010001001 |
3 | 1201111100000000021111210002 |
4 | 2333011122103330202021 |
5 | 3210120224412430433 |
6 | 43532223123132345 |
7 | 2523462061043441 |
oct | 277053223744211 |
9 | 51440000244702 |
10 | 13131230201993 |
11 | 4202a18133892 |
12 | 1580b065140b5 |
13 | 74336769a307 |
14 | 3357aaa43121 |
15 | 17b8904ee9e8 |
hex | bf15a4fc889 |
13131230201993 has 2 divisors, whose sum is σ = 13131230201994. Its totient is φ = 13131230201992.
The previous prime is 13131230201987. The next prime is 13131230202067. The reversal of 13131230201993 is 39910203213131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 13098123671689 + 33106530304 = 3619133^2 + 181952^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13131230201993 is a prime.
It is not a weakly prime, because it can be changed into another prime (13131230201393) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565615100996 + 6565615100997.
It is an arithmetic number, because the mean of its divisors is an integer number (6565615100997).
Almost surely, 213131230201993 is an apocalyptic number.
It is an amenable number.
13131230201993 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131230201993 is an equidigital number, since it uses as much as digits as its factorization.
13131230201993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26244, while the sum is 38.
The spelling of 13131230201993 in words is "thirteen trillion, one hundred thirty-one billion, two hundred thirty million, two hundred one thousand, nine hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •