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13131240442031 is a prime number
BaseRepresentation
bin1011111100010101101011…
…1011000000100010101111
31201111100000201112202110202
42333011122323000202233
53210120240023121111
643532224130424115
72523462244062665
oct277053273004257
951440021482422
1013131240442031
114202a22998328
121580b09a3203b
137433698441ca
143357ac14ac35
1517b891373b3b
hexbf15aec08af

13131240442031 has 2 divisors, whose sum is σ = 13131240442032. Its totient is φ = 13131240442030.

The previous prime is 13131240442007. The next prime is 13131240442079. The reversal of 13131240442031 is 13024404213131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13131240442031 - 218 = 13131240179887 is a prime.

It is a super-2 number, since 2×131312404420312 (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13131240441985 and 13131240442003.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13131240445031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565620221015 + 6565620221016.

It is an arithmetic number, because the mean of its divisors is an integer number (6565620221016).

Almost surely, 213131240442031 is an apocalyptic number.

13131240442031 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131240442031 is an equidigital number, since it uses as much as digits as its factorization.

13131240442031 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 6912, while the sum is 29.

Adding to 13131240442031 its reverse (13024404213131), we get a palindrome (26155644655162).

The spelling of 13131240442031 in words is "thirteen trillion, one hundred thirty-one billion, two hundred forty million, four hundred forty-two thousand, thirty-one".