13131301400011 has 2 divisors, whose sum is σ = 13131301400012. Its totient is φ = 13131301400010.

The previous prime is 13131301399999. The next prime is 13131301400017. The reversal of 13131301400011 is 11000410313131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13131301400011 - 2¹⁵ = 13131301367243 is a prime.

It is a super-3 number, since 3×13131301400011³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (13131301400017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565650700005 + 6565650700006.

It is an arithmetic number, because the mean of its divisors is an integer number (6565650700006).

Almost surely, 2^{13131301400011} is an apocalyptic number.

13131301400011 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131301400011 is an equidigital number, since it uses as much as digits as its factorization.

13131301400011 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 13131301400011 its reverse (11000410313131), we get a palindrome (24131711713142).

The spelling of 13131301400011 in words is "thirteen trillion, one hundred thirty-one billion, three hundred one million, four hundred thousand, eleven".