Base | Representation |
---|---|
bin | 11000011101010111… |
… | …11110100011110111 |
3 | 1020220010212201202212 |
4 | 30032223332203313 |
5 | 203343103430401 |
6 | 10011001324035 |
7 | 643256206364 |
oct | 141653764367 |
9 | 36803781685 |
10 | 13131311351 |
11 | 5629312634 |
12 | 266579661b |
13 | 1313659322 |
14 | 8c7d8b46b |
15 | 51cc3ddbb |
hex | 30eafe8f7 |
13131311351 has 2 divisors, whose sum is σ = 13131311352. Its totient is φ = 13131311350.
The previous prime is 13131311251. The next prime is 13131311381. The reversal of 13131311351 is 15311313131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13131311351 - 210 = 13131310327 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13131311381) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565655675 + 6565655676.
It is an arithmetic number, because the mean of its divisors is an integer number (6565655676).
Almost surely, 213131311351 is an apocalyptic number.
13131311351 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131311351 is an equidigital number, since it uses as much as digits as its factorization.
13131311351 is an evil number, because the sum of its binary digits is even.
The product of its digits is 405, while the sum is 23.
Adding to 13131311351 its reverse (15311313131), we get a palindrome (28442624482).
The spelling of 13131311351 in words is "thirteen billion, one hundred thirty-one million, three hundred eleven thousand, three hundred fifty-one".
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