Base | Representation |
---|---|
bin | 1011111100010110001001… |
… | …1100010001011011010010 |
3 | 1201111100100111221101000212 |
4 | 2333011202130101123102 |
5 | 3210121014322234300 |
6 | 43532244434444122 |
7 | 2523465335322425 |
oct | 277054234213322 |
9 | 51440314841025 |
10 | 13131366602450 |
11 | 4202a88127538 |
12 | 1580b44133642 |
13 | 743389a17145 |
14 | 3357c0bcb9bc |
15 | 17b89c494935 |
hex | bf1627116d2 |
13131366602450 has 48 divisors (see below), whose sum is σ = 24438450526560. Its totient is φ = 5249513425920.
The previous prime is 13131366602447. The next prime is 13131366602461. The reversal of 13131366602450 is 5420666313131.
13131366602450 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 13131366602398 and 13131366602407.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1258632434 + ... + 1258642866.
It is an arithmetic number, because the mean of its divisors is an integer number (509134385970).
Almost surely, 213131366602450 is an apocalyptic number.
13131366602450 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13131366602450 is a deficient number, since it is larger than the sum of its proper divisors (11307083924110).
13131366602450 is a wasteful number, since it uses less digits than its factorization.
13131366602450 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22571 (or 22566 counting only the distinct ones).
The product of its (nonzero) digits is 233280, while the sum is 41.
The spelling of 13131366602450 in words is "thirteen trillion, one hundred thirty-one billion, three hundred sixty-six million, six hundred two thousand, four hundred fifty".
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