13131400233491 has 2 divisors, whose sum is σ = 13131400233492. Its totient is φ = 13131400233490.

The previous prime is 13131400233443. The next prime is 13131400233493. The reversal of 13131400233491 is 19433200413131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13131400233491 is a prime.

Together with 13131400233493, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13131400233493) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565700116745 + 6565700116746.

It is an arithmetic number, because the mean of its divisors is an integer number (6565700116746).

Almost surely, 2^{13131400233491} is an apocalyptic number.

13131400233491 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131400233491 is an equidigital number, since it uses as much as digits as its factorization.

13131400233491 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 23328, while the sum is 35.

The spelling of 13131400233491 in words is "thirteen trillion, one hundred thirty-one billion, four hundred million, two hundred thirty-three thousand, four hundred ninety-one".