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13131400234102 = 2152319237224101
BaseRepresentation
bin1011111100010110010001…
…1100100100010001110110
31201111100102212020000222121
42333011210130210101312
53210121101424442402
643532252035350154
72523466224225043
oct277054434442166
951440385200877
1013131400234102
114202aa5108497
121580b5345235a
13743393991127
143357c54641ca
1517b8a03d9837
hexbf164724476

13131400234102 has 16 divisors (see below), whose sum is σ = 19711145989872. Its totient is φ = 6561018727200.

The previous prime is 13131400234093. The next prime is 13131400234111. The reversal of 13131400234102 is 20143200413131.

13131400234102 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (13131400234093) and next prime (13131400234111).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 58483852 + ... + 58707952.

It is an arithmetic number, because the mean of its divisors is an integer number (1231946624367).

Almost surely, 213131400234102 is an apocalyptic number.

13131400234102 is a deficient number, since it is larger than the sum of its proper divisors (6579745755770).

13131400234102 is a wasteful number, since it uses less digits than its factorization.

13131400234102 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 244863.

The product of its (nonzero) digits is 1728, while the sum is 25.

Adding to 13131400234102 its reverse (20143200413131), we get a palindrome (33274600647233).

The spelling of 13131400234102 in words is "thirteen trillion, one hundred thirty-one billion, four hundred million, two hundred thirty-four thousand, one hundred two".

Divisors: 1 2 1523 3046 19237 38474 224101 448202 29297951 58595902 341305823 682611646 4311030937 8622061874 6565700117051 13131400234102