Base | Representation |
---|---|
bin | 1011111100010110011001… |
… | …0010011001010101000001 |
3 | 1201111100112000100022112202 |
4 | 2333011212102121111001 |
5 | 3210121132331402431 |
6 | 43532255101402545 |
7 | 2523500050612655 |
oct | 277054622312501 |
9 | 51440460308482 |
10 | 13131431122241 |
11 | 4203010595183 |
12 | 1580b61869455 |
13 | 74339a1b7433 |
14 | 3357c95c4a65 |
15 | 17b8a2e8b8cb |
hex | bf166499541 |
13131431122241 has 2 divisors, whose sum is σ = 13131431122242. Its totient is φ = 13131431122240.
The previous prime is 13131431122217. The next prime is 13131431122273. The reversal of 13131431122241 is 14222113413131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 6712783537216 + 6418647585025 = 2590904^2 + 2533505^2 .
It is a cyclic number.
It is not a de Polignac number, because 13131431122241 - 26 = 13131431122177 is a prime.
It is not a weakly prime, because it can be changed into another prime (13131431122441) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565715561120 + 6565715561121.
It is an arithmetic number, because the mean of its divisors is an integer number (6565715561121).
Almost surely, 213131431122241 is an apocalyptic number.
It is an amenable number.
13131431122241 is a deficient number, since it is larger than the sum of its proper divisors (1).
13131431122241 is an equidigital number, since it uses as much as digits as its factorization.
13131431122241 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 3456, while the sum is 29.
Adding to 13131431122241 its reverse (14222113413131), we get a palindrome (27353544535372).
The spelling of 13131431122241 in words is "thirteen trillion, one hundred thirty-one billion, four hundred thirty-one million, one hundred twenty-two thousand, two hundred forty-one".
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