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13131431122441 is a prime number
BaseRepresentation
bin1011111100010110011001…
…0010011001011000001001
31201111100112000100022211011
42333011212102121120021
53210121132331404231
643532255101403521
72523500050613362
oct277054622313011
951440460308734
1013131431122441
114203010595345
121580b618695a1
1374339a1b7558
143357c95c4b69
1517b8a2e8b9b1
hexbf166499609

13131431122441 has 2 divisors, whose sum is σ = 13131431122442. Its totient is φ = 13131431122440.

The previous prime is 13131431122391. The next prime is 13131431122483. The reversal of 13131431122441 is 14422113413131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9116196644416 + 4015234478025 = 3019304^2 + 2003805^2 .

It is a cyclic number.

It is not a de Polignac number, because 13131431122441 - 221 = 13131429025289 is a prime.

It is a super-2 number, since 2×131314311224412 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (13131431122241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6565715561220 + 6565715561221.

It is an arithmetic number, because the mean of its divisors is an integer number (6565715561221).

Almost surely, 213131431122441 is an apocalyptic number.

It is an amenable number.

13131431122441 is a deficient number, since it is larger than the sum of its proper divisors (1).

13131431122441 is an equidigital number, since it uses as much as digits as its factorization.

13131431122441 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 6912, while the sum is 31.

Adding to 13131431122441 its reverse (14422113413131), we get a palindrome (27553544535572).

The spelling of 13131431122441 in words is "thirteen trillion, one hundred thirty-one billion, four hundred thirty-one million, one hundred twenty-two thousand, four hundred forty-one".