Base | Representation |
---|---|
bin | 10011000110111101011… |
… | …011011100001000110000 |
3 | 11122112110012102201202222 |
4 | 103012331123130020300 |
5 | 133003304114042430 |
6 | 2443125530100212 |
7 | 163604624201021 |
oct | 23067533341060 |
9 | 4575405381688 |
10 | 1313143112240 |
11 | 4669a0064a23 |
12 | 1925b4b7a668 |
13 | 96aa1025c2b |
14 | 477b0d28c48 |
15 | 24257be59e5 |
hex | 131bd6dc230 |
1313143112240 has 40 divisors (see below), whose sum is σ = 3054007373280. Its totient is φ = 525093866496.
The previous prime is 1313143112233. The next prime is 1313143112249. The reversal of 1313143112240 is 422113413131.
It is a tau number, because it is divible by the number of its divisors (40).
It is not an unprimeable number, because it can be changed into a prime (1313143112249) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2293820 + ... + 2808539.
It is an arithmetic number, because the mean of its divisors is an integer number (76350184332).
Almost surely, 21313143112240 is an apocalyptic number.
1313143112240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1313143112240 is an abundant number, since it is smaller than the sum of its proper divisors (1740864261040).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1313143112240 is a wasteful number, since it uses less digits than its factorization.
1313143112240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5105589 (or 5105583 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 26.
Adding to 1313143112240 its reverse (422113413131), we get a palindrome (1735256525371).
The spelling of 1313143112240 in words is "one trillion, three hundred thirteen billion, one hundred forty-three million, one hundred twelve thousand, two hundred forty".
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