13131431122442 has 4 divisors (see below), whose sum is σ = 19697146683666. Its totient is φ = 6565715561220.

The previous prime is 13131431122441. The next prime is 13131431122483. The reversal of 13131431122442 is 24422113413131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12327254418361 + 804176704081 = 3511019^2 + 896759^2 .

It is a junction number, because it is equal to n+sod(n) for n = 13131431122399 and 13131431122408.

It is not an unprimeable number, because it can be changed into a prime (13131431122441) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282857780609 + ... + 3282857780612.

Almost surely, 2^{13131431122442} is an apocalyptic number.

13131431122442 is a deficient number, since it is larger than the sum of its proper divisors (6565715561224).

13131431122442 is an equidigital number, since it uses as much as digits as its factorization.

13131431122442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6565715561223.

The product of its digits is 13824, while the sum is 32.

Adding to 13131431122442 its reverse (24422113413131), we get a palindrome (37553544535573).

The spelling of 13131431122442 in words is "thirteen trillion, one hundred thirty-one billion, four hundred thirty-one million, one hundred twenty-two thousand, four hundred forty-two".