Base | Representation |
---|---|
bin | 1011111100010110011100… |
… | …0011111110111011110010 |
3 | 1201111100112220210201221111 |
4 | 2333011213003332323302 |
5 | 3210121144143340310 |
6 | 43532300244143534 |
7 | 2523500266243123 |
oct | 277054703767362 |
9 | 51440486721844 |
10 | 13131444121330 |
11 | 4203017963627 |
12 | 1580b66097baa |
13 | 74339cab90c2 |
14 | 3357cb20a04a |
15 | 17b8a41a828a |
hex | bf1670feef2 |
13131444121330 has 128 divisors (see below), whose sum is σ = 25513182282240. Its totient is φ = 4848522117120.
The previous prime is 13131444121309. The next prime is 13131444121339. The reversal of 13131444121330 is 3312144413131.
It is a super-2 number, since 2×131314441213302 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13131444121292 and 13131444121301.
It is not an unprimeable number, because it can be changed into a prime (13131444121339) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5188242165 + ... + 5188244695.
It is an arithmetic number, because the mean of its divisors is an integer number (199321736580).
Almost surely, 213131444121330 is an apocalyptic number.
13131444121330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13131444121330 is a deficient number, since it is larger than the sum of its proper divisors (12381738160910).
13131444121330 is a wasteful number, since it uses less digits than its factorization.
13131444121330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5284.
The product of its (nonzero) digits is 10368, while the sum is 31.
Adding to 13131444121330 its reverse (3312144413131), we get a palindrome (16443588534461).
The spelling of 13131444121330 in words is "thirteen trillion, one hundred thirty-one billion, four hundred forty-four million, one hundred twenty-one thousand, three hundred thirty".
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