Base | Representation |
---|---|
bin | 10011000110111101101… |
… | …000111001000011010011 |
3 | 11122112110110001212221221 |
4 | 103012331220321003103 |
5 | 133003311014413142 |
6 | 2443130133425511 |
7 | 163604666155552 |
oct | 23067550710323 |
9 | 4575413055857 |
10 | 1313146638547 |
11 | 4669a2053327 |
12 | 1925b619b297 |
13 | 96aa198bcc3 |
14 | 477b15a5d99 |
15 | 24258190767 |
hex | 131bda390d3 |
1313146638547 has 2 divisors, whose sum is σ = 1313146638548. Its totient is φ = 1313146638546.
The previous prime is 1313146638511. The next prime is 1313146638593. The reversal of 1313146638547 is 7458366413131.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1313146638547 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313146638494 and 1313146638503.
It is not a weakly prime, because it can be changed into another prime (1313146638247) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656573319273 + 656573319274.
It is an arithmetic number, because the mean of its divisors is an integer number (656573319274).
Almost surely, 21313146638547 is an apocalyptic number.
1313146638547 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313146638547 is an equidigital number, since it uses as much as digits as its factorization.
1313146638547 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 4354560, while the sum is 52.
The spelling of 1313146638547 in words is "one trillion, three hundred thirteen billion, one hundred forty-six million, six hundred thirty-eight thousand, five hundred forty-seven".
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