Base | Representation |
---|---|
bin | 10011000110111101101… |
… | …000111001000010101111 |
3 | 11122112110110001212220121 |
4 | 103012331220321002233 |
5 | 133003311014413021 |
6 | 2443130133425411 |
7 | 163604666155501 |
oct | 23067550710257 |
9 | 4575413055817 |
10 | 1313146638511 |
11 | 4669a20532a4 |
12 | 1925b619b267 |
13 | 96aa198bc96 |
14 | 477b15a5d71 |
15 | 24258190741 |
hex | 131bda390af |
1313146638511 has 2 divisors, whose sum is σ = 1313146638512. Its totient is φ = 1313146638510.
The previous prime is 1313146638509. The next prime is 1313146638547. The reversal of 1313146638511 is 1158366413131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1313146638511 - 21 = 1313146638509 is a prime.
It is a super-3 number, since 3×13131466385113 (a number of 37 digits) contains 333 as substring.
Together with 1313146638509, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313146635511) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656573319255 + 656573319256.
It is an arithmetic number, because the mean of its divisors is an integer number (656573319256).
Almost surely, 21313146638511 is an apocalyptic number.
1313146638511 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313146638511 is an equidigital number, since it uses as much as digits as its factorization.
1313146638511 is an evil number, because the sum of its binary digits is even.
The product of its digits is 155520, while the sum is 43.
The spelling of 1313146638511 in words is "one trillion, three hundred thirteen billion, one hundred forty-six million, six hundred thirty-eight thousand, five hundred eleven".
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