Base | Representation |
---|---|
bin | 111101001001100000… |
… | …0010001001011100000 |
3 | 110112221120222102220010 |
4 | 1322103000101023200 |
5 | 4122413211340000 |
6 | 140154143244520 |
7 | 12326054654565 |
oct | 1722300211340 |
9 | 415846872803 |
10 | 131315340000 |
11 | 507660a4589 |
12 | 215492a9740 |
13 | c4c9550b20 |
14 | 64da06086c |
15 | 3638583d50 |
hex | 1e930112e0 |
131315340000 has 240 divisors, whose sum is σ = 463877224272. Its totient is φ = 32323584000.
The previous prime is 131315339999. The next prime is 131315340019. The reversal of 131315340000 is 43513131.
It is a tau number, because it is divible by the number of its divisors (240).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 695824 + ... + 864176.
Almost surely, 2131315340000 is an apocalyptic number.
131315340000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131315340000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (231938612136).
131315340000 is an abundant number, since it is smaller than the sum of its proper divisors (332561884272).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131315340000 is a wasteful number, since it uses less digits than its factorization.
131315340000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 168399 (or 168376 counting only the distinct ones).
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 131315340000 its reverse (43513131), we get a palindrome (131358853131).
The spelling of 131315340000 in words is "one hundred thirty-one billion, three hundred fifteen million, three hundred forty thousand".
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