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13131544012534 = 26565772006267
BaseRepresentation
bin1011111100010110110100…
…0001000010011011110110
31201111100210212202201220201
42333011231001002123312
53210121400231400114
643532314213151114
72523502621303123
oct277055501023366
951440725681821
1013131544012534
114203069290342
121580b9362b49a
137433b76c221c
143357da5ad74a
1517b8acd3a874
hexbf16d0426f6

13131544012534 has 4 divisors (see below), whose sum is σ = 19697316018804. Its totient is φ = 6565772006266.

The previous prime is 13131544012523. The next prime is 13131544012547. The reversal of 13131544012534 is 43521044513131.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 13131544012493 and 13131544012502.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282886003132 + ... + 3282886003135.

It is an arithmetic number, because the mean of its divisors is an integer number (4924329004701).

Almost surely, 213131544012534 is an apocalyptic number.

13131544012534 is a deficient number, since it is larger than the sum of its proper divisors (6565772006270).

13131544012534 is an equidigital number, since it uses as much as digits as its factorization.

13131544012534 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6565772006269.

The product of its (nonzero) digits is 86400, while the sum is 37.

Adding to 13131544012534 its reverse (43521044513131), we get a palindrome (56652588525665).

The spelling of 13131544012534 in words is "thirteen trillion, one hundred thirty-one billion, five hundred forty-four million, twelve thousand, five hundred thirty-four".

Divisors: 1 2 6565772006267 13131544012534