Base | Representation |
---|---|
bin | 1011111100010110110100… |
… | …0001000010011011110110 |
3 | 1201111100210212202201220201 |
4 | 2333011231001002123312 |
5 | 3210121400231400114 |
6 | 43532314213151114 |
7 | 2523502621303123 |
oct | 277055501023366 |
9 | 51440725681821 |
10 | 13131544012534 |
11 | 4203069290342 |
12 | 1580b9362b49a |
13 | 7433b76c221c |
14 | 3357da5ad74a |
15 | 17b8acd3a874 |
hex | bf16d0426f6 |
13131544012534 has 4 divisors (see below), whose sum is σ = 19697316018804. Its totient is φ = 6565772006266.
The previous prime is 13131544012523. The next prime is 13131544012547. The reversal of 13131544012534 is 43521044513131.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a junction number, because it is equal to n+sod(n) for n = 13131544012493 and 13131544012502.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3282886003132 + ... + 3282886003135.
It is an arithmetic number, because the mean of its divisors is an integer number (4924329004701).
Almost surely, 213131544012534 is an apocalyptic number.
13131544012534 is a deficient number, since it is larger than the sum of its proper divisors (6565772006270).
13131544012534 is an equidigital number, since it uses as much as digits as its factorization.
13131544012534 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 6565772006269.
The product of its (nonzero) digits is 86400, while the sum is 37.
Adding to 13131544012534 its reverse (43521044513131), we get a palindrome (56652588525665).
The spelling of 13131544012534 in words is "thirteen trillion, one hundred thirty-one billion, five hundred forty-four million, twelve thousand, five hundred thirty-four".
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