131320230331240 has 64 divisors (see below), whose sum is σ = 295998209280000. Its totient is φ = 52434285657600.

The previous prime is 131320230331231. The next prime is 131320230331247. The reversal of 131320230331240 is 42133032023131.

It is a junction number, because it is equal to n+sod(n) for n = 131320230331199 and 131320230331208.

It is not an unprimeable number, because it can be changed into a prime (131320230331247) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1164140361 + ... + 1164253159.

It is an arithmetic number, because the mean of its divisors is an integer number (4624972020000).

Almost surely, 2^{131320230331240} is an apocalyptic number.

131320230331240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131320230331240 is an abundant number, since it is smaller than the sum of its proper divisors (164677978948760).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131320230331240 is a wasteful number, since it uses less digits than its factorization.

131320230331240 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 164530 (or 164526 counting only the distinct ones).

The product of its (nonzero) digits is 7776, while the sum is 28.

Adding to 131320230331240 its reverse (42133032023131), we get a palindrome (173453262354371).

The spelling of 131320230331240 in words is "one hundred thirty-one trillion, three hundred twenty billion, two hundred thirty million, three hundred thirty-one thousand, two hundred forty".