Base | Representation |
---|---|
bin | 11101110110111101100100… |
… | …011100010110101111110011 |
3 | 122012222002200012122022210211 |
4 | 131312331210130112233303 |
5 | 114203022443404330003 |
6 | 1143143415004204551 |
7 | 36442402464404536 |
oct | 3566754434265763 |
9 | 565862605568724 |
10 | 131320310230003 |
11 | 3892a6a367a874 |
12 | 1288a90a239757 |
13 | 58375b53c74ab |
14 | 245dd18d06a1d |
15 | 102ae215b996d |
hex | 776f64716bf3 |
131320310230003 has 2 divisors, whose sum is σ = 131320310230004. Its totient is φ = 131320310230002.
The previous prime is 131320310229917. The next prime is 131320310230013. The reversal of 131320310230003 is 300032013023131.
It is a strong prime.
It is an emirp because it is prime and its reverse (300032013023131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131320310230003 is a prime.
It is a super-2 number, since 2×1313203102300032 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131320310230013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65660155115001 + 65660155115002.
It is an arithmetic number, because the mean of its divisors is an integer number (65660155115002).
Almost surely, 2131320310230003 is an apocalyptic number.
131320310230003 is a deficient number, since it is larger than the sum of its proper divisors (1).
131320310230003 is an equidigital number, since it uses as much as digits as its factorization.
131320310230003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 131320310230003 its reverse (300032013023131), we get a palindrome (431352323253134).
The spelling of 131320310230003 in words is "one hundred thirty-one trillion, three hundred twenty billion, three hundred ten million, two hundred thirty thousand, three".
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