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13132111561 is a prime number
BaseRepresentation
bin11000011101011110…
…00001111011001001
31020220012101101110021
430032233001323021
5203343310032221
610011030420441
7643266051352
oct141657017311
936805341407
1013132111561
115629809868
122665b01721
13131387961a
148c8118d29
1551cd4b041
hex30ebc1ec9

13132111561 has 2 divisors, whose sum is σ = 13132111562. Its totient is φ = 13132111560.

The previous prime is 13132111511. The next prime is 13132111583. The reversal of 13132111561 is 16511123131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12940427536 + 191684025 = 113756^2 + 13845^2 .

It is an emirp because it is prime and its reverse (16511123131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13132111561 - 217 = 13131980489 is a prime.

It is not a weakly prime, because it can be changed into another prime (13132111501) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566055780 + 6566055781.

It is an arithmetic number, because the mean of its divisors is an integer number (6566055781).

Almost surely, 213132111561 is an apocalyptic number.

It is an amenable number.

13132111561 is a deficient number, since it is larger than the sum of its proper divisors (1).

13132111561 is an equidigital number, since it uses as much as digits as its factorization.

13132111561 is an evil number, because the sum of its binary digits is even.

The product of its digits is 540, while the sum is 25.

Adding to 13132111561 its reverse (16511123131), we get a palindrome (29643234692).

The spelling of 13132111561 in words is "thirteen billion, one hundred thirty-two million, one hundred eleven thousand, five hundred sixty-one".