Base | Representation |
---|---|
bin | 10011000111000001100… |
… | …110011110001111010101 |
3 | 11122112122002011011011212 |
4 | 103013001212132033111 |
5 | 133003430024111201 |
6 | 2443140510311205 |
7 | 163606434200525 |
oct | 23070146361725 |
9 | 4575562134155 |
10 | 1313213113301 |
11 | 466a26626841 |
12 | 1926144b8505 |
13 | 96ab269508b |
14 | 477ba34b685 |
15 | 2425de21abb |
hex | 131c199e3d5 |
1313213113301 has 2 divisors, whose sum is σ = 1313213113302. Its totient is φ = 1313213113300.
The previous prime is 1313213113297. The next prime is 1313213113309. The reversal of 1313213113301 is 1033113123131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 926079028900 + 387134084401 = 962330^2 + 622201^2 .
It is a cyclic number.
It is not a de Polignac number, because 1313213113301 - 22 = 1313213113297 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1313213113309) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656606556650 + 656606556651.
It is an arithmetic number, because the mean of its divisors is an integer number (656606556651).
Almost surely, 21313213113301 is an apocalyptic number.
It is an amenable number.
1313213113301 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313213113301 is an equidigital number, since it uses as much as digits as its factorization.
1313213113301 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 1313213113301 its reverse (1033113123131), we get a palindrome (2346326236432).
The spelling of 1313213113301 in words is "one trillion, three hundred thirteen billion, two hundred thirteen million, one hundred thirteen thousand, three hundred one".
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