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131322021132000 = 25353472414792017
BaseRepresentation
bin11101110110111111001010…
…011010111011011011100000
3122012222021002110000011010110
4131312333022122323123200
5114203034444402211000
61143144300442531320
736442463051004156
oct3566771232733340
9565867073004113
10131322021132000
11389303a1409866
121288b107206b40
1358377c89c003a
14246003c2293d6
15102aec18c3850
hex776fca6bb6e0

131322021132000 has 768 divisors, whose sum is σ = 442327704698880. Its totient is φ = 34043756544000.

The previous prime is 131322021131999. The next prime is 131322021132013. The reversal of 131322021132000 is 231120223131.

It is a super-2 number, since 2×1313220211320002 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 65107594992 + ... + 65107597008.

It is an arithmetic number, because the mean of its divisors is an integer number (575947532160).

Almost surely, 2131322021132000 is an apocalyptic number.

131322021132000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131322021132000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (221163852349440).

131322021132000 is an abundant number, since it is smaller than the sum of its proper divisors (311005683566880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131322021132000 is a wasteful number, since it uses less digits than its factorization.

131322021132000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2812 (or 2794 counting only the distinct ones).

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 131322021132000 its reverse (231120223131), we get a palindrome (131553141355131).

The spelling of 131322021132000 in words is "one hundred thirty-one trillion, three hundred twenty-two billion, twenty-one million, one hundred thirty-two thousand".