Base | Representation |
---|---|
bin | 10011000111000010010… |
… | …000000001011001101001 |
3 | 11122112122211122112002110 |
4 | 103013002100001121221 |
5 | 133003440321131400 |
6 | 2443141535552533 |
7 | 163606625603436 |
oct | 23070220013151 |
9 | 4575584575073 |
10 | 1313224005225 |
11 | 466a31796030 |
12 | 19261808b749 |
13 | 96ab4a098c2 |
14 | 477bb984b8d |
15 | 2425ed73e50 |
hex | 131c2401669 |
1313224005225 has 24 divisors (see below), whose sum is σ = 2368578570912. Its totient is φ = 636714668800.
The previous prime is 1313224005143. The next prime is 1313224005253. The reversal of 1313224005225 is 5225004223131.
It is not a de Polignac number, because 1313224005225 - 211 = 1313224003177 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1313224005192 and 1313224005201.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 795892512 + ... + 795894161.
It is an arithmetic number, because the mean of its divisors is an integer number (98690773788).
Almost surely, 21313224005225 is an apocalyptic number.
1313224005225 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1313224005225 is a deficient number, since it is larger than the sum of its proper divisors (1055354565687).
1313224005225 is a wasteful number, since it uses less digits than its factorization.
1313224005225 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1591786697 (or 1591786692 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 30.
Adding to 1313224005225 its reverse (5225004223131), we get a palindrome (6538228228356).
The spelling of 1313224005225 in words is "one trillion, three hundred thirteen billion, two hundred twenty-four million, five thousand, two hundred twenty-five".
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