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13132311423043 is a prime number
BaseRepresentation
bin1011111100011001101011…
…0000011110100001000011
31201111102210100210020020011
42333012122300132201003
53210124433211014133
643532522305325351
72523530630214421
oct277063260364103
951442710706204
1013132311423043
1142034224921aa
121581168636857
137434aa6a4597
14335870494111
1517b9053c66cd
hexbf19ac1e843

13132311423043 has 2 divisors, whose sum is σ = 13132311423044. Its totient is φ = 13132311423042.

The previous prime is 13132311423041. The next prime is 13132311423059. The reversal of 13132311423043 is 34032411323131.

13132311423043 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13132311423043 - 21 = 13132311423041 is a prime.

It is a super-2 number, since 2×131323114230432 (a number of 27 digits) contains 22 as substring.

Together with 13132311423041, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13132311422996 and 13132311423014.

It is not a weakly prime, because it can be changed into another prime (13132311423041) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566155711521 + 6566155711522.

It is an arithmetic number, because the mean of its divisors is an integer number (6566155711522).

Almost surely, 213132311423043 is an apocalyptic number.

13132311423043 is a deficient number, since it is larger than the sum of its proper divisors (1).

13132311423043 is an equidigital number, since it uses as much as digits as its factorization.

13132311423043 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15552, while the sum is 31.

Adding to 13132311423043 its reverse (34032411323131), we get a palindrome (47164722746174).

The spelling of 13132311423043 in words is "thirteen trillion, one hundred thirty-two billion, three hundred eleven million, four hundred twenty-three thousand, forty-three".