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13132312230049 is a prime number
BaseRepresentation
bin1011111100011001101011…
…0011100011100010100001
31201111102210102022020020021
42333012122303203202201
53210124433412330144
643532522334513441
72523530640115255
oct277063263434241
951442712266207
1013132312230049
114203422993551
121581168965881
137434aa8c79bc
14335870624265
1517b9054d5884
hexbf19ace38a1

13132312230049 has 2 divisors, whose sum is σ = 13132312230050. Its totient is φ = 13132312230048.

The previous prime is 13132312229999. The next prime is 13132312230071. The reversal of 13132312230049 is 94003221323131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9030067070049 + 4102245160000 = 3005007^2 + 2025400^2 .

It is a cyclic number.

It is not a de Polignac number, because 13132312230049 - 215 = 13132312197281 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13132312229996 and 13132312230023.

It is not a weakly prime, because it can be changed into another prime (13132312210049) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566156115024 + 6566156115025.

It is an arithmetic number, because the mean of its divisors is an integer number (6566156115025).

Almost surely, 213132312230049 is an apocalyptic number.

It is an amenable number.

13132312230049 is a deficient number, since it is larger than the sum of its proper divisors (1).

13132312230049 is an equidigital number, since it uses as much as digits as its factorization.

13132312230049 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 23328, while the sum is 34.

The spelling of 13132312230049 in words is "thirteen trillion, one hundred thirty-two billion, three hundred twelve million, two hundred thirty thousand, forty-nine".