Base | Representation |
---|---|
bin | 1011111100011001110010… |
… | …0010001001111110001110 |
3 | 1201111102212102212020111202 |
4 | 2333012130202021332032 |
5 | 3210130013323121220 |
6 | 43532525252145502 |
7 | 2523531441421601 |
oct | 277063442117616 |
9 | 51442772766452 |
10 | 13132341223310 |
11 | 4203438296621 |
12 | 1581176608292 |
13 | 7434b390968a |
14 | 335874410338 |
15 | 17b907d11275 |
hex | bf19c889f8e |
13132341223310 has 8 divisors (see below), whose sum is σ = 23638214201976. Its totient is φ = 5252936489320.
The previous prime is 13132341223291. The next prime is 13132341223357. The reversal of 13132341223310 is 1332214323131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a super-2 number, since 2×131323412233102 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 656617061156 + ... + 656617061175.
It is an arithmetic number, because the mean of its divisors is an integer number (2954776775247).
Almost surely, 213132341223310 is an apocalyptic number.
13132341223310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13132341223310 is a deficient number, since it is larger than the sum of its proper divisors (10505872978666).
13132341223310 is a wasteful number, since it uses less digits than its factorization.
13132341223310 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1313234122338.
The product of its (nonzero) digits is 7776, while the sum is 29.
Adding to 13132341223310 its reverse (1332214323131), we get a palindrome (14464555546441).
The spelling of 13132341223310 in words is "thirteen trillion, one hundred thirty-two billion, three hundred forty-one million, two hundred twenty-three thousand, three hundred ten".
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