1313241200437 has 2 divisors, whose sum is σ = 1313241200438. Its totient is φ = 1313241200436.

The previous prime is 1313241200417. The next prime is 1313241200471. The reversal of 1313241200437 is 7340021423131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1269657957681 + 43583242756 = 1126791^2 + 208766^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313241200437 - 2¹¹ = 1313241198389 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1313241200399 and 1313241200408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313241200417) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656620600218 + 656620600219.

It is an arithmetic number, because the mean of its divisors is an integer number (656620600219).

Almost surely, 2^{1313241200437} is an apocalyptic number.

It is an amenable number.

1313241200437 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313241200437 is an equidigital number, since it uses as much as digits as its factorization.

1313241200437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 12096, while the sum is 31.

Adding to 1313241200437 its reverse (7340021423131), we get a palindrome (8653262623568).

The spelling of 1313241200437 in words is "one trillion, three hundred thirteen billion, two hundred forty-one million, two hundred thousand, four hundred thirty-seven".