Base | Representation |
---|---|
bin | 10011000111000011010… |
… | …001100111011100111101 |
3 | 11122112201001000010111110 |
4 | 103013003101213130331 |
5 | 133004004221403240 |
6 | 2443143352312233 |
7 | 163610225011326 |
oct | 23070321473475 |
9 | 4575631003443 |
10 | 1313241200445 |
11 | 466a40470059 |
12 | 1926219a2679 |
13 | 96ab844a4a5 |
14 | 477bdd7d44d |
15 | 2426161dc80 |
hex | 131c346773d |
1313241200445 has 8 divisors (see below), whose sum is σ = 2101185920736. Its totient is φ = 700395306896.
The previous prime is 1313241200437. The next prime is 1313241200471. The reversal of 1313241200445 is 5440021423131.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 1313241200445 - 23 = 1313241200437 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 43774706667 + ... + 43774706696.
It is an arithmetic number, because the mean of its divisors is an integer number (262648240092).
Almost surely, 21313241200445 is an apocalyptic number.
1313241200445 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1313241200445 is a deficient number, since it is larger than the sum of its proper divisors (787944720291).
1313241200445 is an equidigital number, since it uses as much as digits as its factorization.
1313241200445 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 87549413371.
The product of its (nonzero) digits is 11520, while the sum is 30.
Adding to 1313241200445 its reverse (5440021423131), we get a palindrome (6753262623576).
The spelling of 1313241200445 in words is "one trillion, three hundred thirteen billion, two hundred forty-one million, two hundred thousand, four hundred forty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.101 sec. • engine limits •