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131325255310 = 2513132525531
BaseRepresentation
bin111101001001110011…
…0000101111010001110
3110112222021122012010211
41322103212011322032
54122423231132220
6140155135553034
712326235152314
oct1722346057216
9415867565124
10131325255310
1150770757057
122155068b77a
13c4cb612c82
1464db4c20b4
153639391b5a
hex1e93985e8e

131325255310 has 8 divisors (see below), whose sum is σ = 236385459576. Its totient is φ = 52530102120.

The previous prime is 131325255301. The next prime is 131325255361. The reversal of 131325255310 is 13552523131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-4 number, since 4×1313252553104 (a number of 46 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 6566262756 + ... + 6566262775.

It is an arithmetic number, because the mean of its divisors is an integer number (29548182447).

Almost surely, 2131325255310 is an apocalyptic number.

131325255310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

131325255310 is a deficient number, since it is larger than the sum of its proper divisors (105060204266).

131325255310 is a wasteful number, since it uses less digits than its factorization.

131325255310 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13132525538.

The product of its (nonzero) digits is 13500, while the sum is 31.

Adding to 131325255310 its reverse (13552523131), we get a palindrome (144877778441).

The spelling of 131325255310 in words is "one hundred thirty-one billion, three hundred twenty-five million, two hundred fifty-five thousand, three hundred ten".

Divisors: 1 2 5 10 13132525531 26265051062 65662627655 131325255310