Base | Representation |
---|---|
bin | 11000011101100001… |
… | …01101111111101001 |
3 | 1020220020012212122221 |
4 | 30032300231333221 |
5 | 203343413213332 |
6 | 10011044114041 |
7 | 643302604036 |
oct | 141660557751 |
9 | 36806185587 |
10 | 13132554217 |
11 | 5629a913a2 |
12 | 2666095921 |
13 | 13139a2c53 |
14 | 8c81d238d |
15 | 51cdd7297 |
hex | 30ec2dfe9 |
13132554217 has 2 divisors, whose sum is σ = 13132554218. Its totient is φ = 13132554216.
The previous prime is 13132554203. The next prime is 13132554223. The reversal of 13132554217 is 71245523131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10854305856 + 2278248361 = 104184^2 + 47731^2 .
It is an emirp because it is prime and its reverse (71245523131) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13132554217 is a prime.
It is not a weakly prime, because it can be changed into another prime (13132552217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566277108 + 6566277109.
It is an arithmetic number, because the mean of its divisors is an integer number (6566277109).
Almost surely, 213132554217 is an apocalyptic number.
It is an amenable number.
13132554217 is a deficient number, since it is larger than the sum of its proper divisors (1).
13132554217 is an equidigital number, since it uses as much as digits as its factorization.
13132554217 is an evil number, because the sum of its binary digits is even.
The product of its digits is 25200, while the sum is 34.
The spelling of 13132554217 in words is "thirteen billion, one hundred thirty-two million, five hundred fifty-four thousand, two hundred seventeen".
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