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1313265397 is a prime number
BaseRepresentation
bin100111001000110…
…1101011011110101
310101112010210110011
41032101231123311
510142143443042
6334151500221
744354400043
oct11621553365
93345123404
101313265397
11614338804
12307987671
1317c100c22
14c65b5393
157a460a17
hex4e46d6f5

1313265397 has 2 divisors, whose sum is σ = 1313265398. Its totient is φ = 1313265396.

The previous prime is 1313265379. The next prime is 1313265403. The reversal of 1313265397 is 7935623131.

Together with previous prime (1313265379) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 864418801 + 448846596 = 29401^2 + 21186^2 .

It is a cyclic number.

It is not a de Polignac number, because 1313265397 - 211 = 1313263349 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1313265337) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656632698 + 656632699.

It is an arithmetic number, because the mean of its divisors is an integer number (656632699).

Almost surely, 21313265397 is an apocalyptic number.

It is an amenable number.

1313265397 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313265397 is an equidigital number, since it uses as much as digits as its factorization.

1313265397 is an evil number, because the sum of its binary digits is even.

The product of its digits is 102060, while the sum is 40.

The square root of 1313265397 is about 36239.0038080519. The cubic root of 1313265397 is about 1095.0925735069.

The spelling of 1313265397 in words is "one billion, three hundred thirteen million, two hundred sixty-five thousand, three hundred ninety-seven".