Base | Representation |
---|---|
bin | 111101001001111011… |
… | …1010110110110110011 |
3 | 110112222121011010110022 |
4 | 1322103313112312303 |
5 | 4122430410444141 |
6 | 140155420554055 |
7 | 12326321502251 |
oct | 1722367266663 |
9 | 415877133408 |
10 | 131329781171 |
11 | 50773268436 |
12 | 215520b292b |
13 | c4cc538cb4 |
14 | 64dbd3d5d1 |
15 | 3639987b4b |
hex | 1e93dd6db3 |
131329781171 has 2 divisors, whose sum is σ = 131329781172. Its totient is φ = 131329781170.
The previous prime is 131329781153. The next prime is 131329781249. The reversal of 131329781171 is 171187923131.
It is a weak prime.
It is an emirp because it is prime and its reverse (171187923131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131329781171 - 210 = 131329780147 is a prime.
It is a super-2 number, since 2×1313297811712 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131329781111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65664890585 + 65664890586.
It is an arithmetic number, because the mean of its divisors is an integer number (65664890586).
Almost surely, 2131329781171 is an apocalyptic number.
131329781171 is a deficient number, since it is larger than the sum of its proper divisors (1).
131329781171 is an equidigital number, since it uses as much as digits as its factorization.
131329781171 is an evil number, because the sum of its binary digits is even.
The product of its digits is 63504, while the sum is 44.
The spelling of 131329781171 in words is "one hundred thirty-one billion, three hundred twenty-nine million, seven hundred eighty-one thousand, one hundred seventy-one".
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