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131329781249 is a prime number
BaseRepresentation
bin111101001001111011…
…1010110111000000001
3110112222121011010120012
41322103313112320001
54122430410444444
6140155420554305
712326321502422
oct1722367267001
9415877133505
10131329781249
11507732684a7
12215520b2995
13c4cc539044
1464dbd3d649
153639987b9e
hex1e93dd6e01

131329781249 has 2 divisors, whose sum is σ = 131329781250. Its totient is φ = 131329781248.

The previous prime is 131329781171. The next prime is 131329781257. The reversal of 131329781249 is 942187923131.

It is a happy number.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 84216040000 + 47113741249 = 290200^2 + 217057^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131329781249 is a prime.

It is a super-2 number, since 2×1313297812492 (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131329781197 and 131329781206.

It is not a weakly prime, because it can be changed into another prime (131329781279) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65664890624 + 65664890625.

It is an arithmetic number, because the mean of its divisors is an integer number (65664890625).

Almost surely, 2131329781249 is an apocalyptic number.

It is an amenable number.

131329781249 is a deficient number, since it is larger than the sum of its proper divisors (1).

131329781249 is an equidigital number, since it uses as much as digits as its factorization.

131329781249 is an evil number, because the sum of its binary digits is even.

The product of its digits is 653184, while the sum is 50.

The spelling of 131329781249 in words is "one hundred thirty-one billion, three hundred twenty-nine million, seven hundred eighty-one thousand, two hundred forty-nine".