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13133045153 is a prime number
BaseRepresentation
bin11000011101100101…
…00101110110100001
31020220021010211002202
430032302211312201
5203344024421103
610011102422545
7643310020244
oct141662456641
936807124082
1013133045153
11562a297228
122666291a55
131313b15547
148c82bd25b
1551ce82988
hex30eca5da1

13133045153 has 2 divisors, whose sum is σ = 13133045154. Its totient is φ = 13133045152.

The previous prime is 13133045147. The next prime is 13133045161. The reversal of 13133045153 is 35154033131.

13133045153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11213115664 + 1919929489 = 105892^2 + 43817^2 .

It is a cyclic number.

It is not a de Polignac number, because 13133045153 - 24 = 13133045137 is a prime.

It is not a weakly prime, because it can be changed into another prime (13133045113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566522576 + 6566522577.

It is an arithmetic number, because the mean of its divisors is an integer number (6566522577).

Almost surely, 213133045153 is an apocalyptic number.

It is an amenable number.

13133045153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13133045153 is an equidigital number, since it uses as much as digits as its factorization.

13133045153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 8100, while the sum is 29.

Adding to 13133045153 its reverse (35154033131), we get a palindrome (48287078284).

The spelling of 13133045153 in words is "thirteen billion, one hundred thirty-three million, forty-five thousand, one hundred fifty-three".