13133045113 has 2 divisors, whose sum is σ = 13133045114. Its totient is φ = 13133045112.

The previous prime is 13133045099. The next prime is 13133045131. The reversal of 13133045113 is 31154033131.

Together with next prime (13133045131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10320121744 + 2812923369 = 101588^2 + 53037^2 .

It is a cyclic number.

It is not a de Polignac number, because 13133045113 - 2²⁵ = 13099490681 is a prime.

It is not a weakly prime, because it can be changed into another prime (13133045153) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566522556 + 6566522557.

It is an arithmetic number, because the mean of its divisors is an integer number (6566522557).

Almost surely, 2^13133045113 is an apocalyptic number.

It is an amenable number.

13133045113 is a deficient number, since it is larger than the sum of its proper divisors (1).

13133045113 is an equidigital number, since it uses as much as digits as its factorization.

13133045113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1620, while the sum is 25.

Adding to 13133045113 its reverse (31154033131), we get a palindrome (44287078244).

The spelling of 13133045113 in words is "thirteen billion, one hundred thirty-three million, forty-five thousand, one hundred thirteen".