Base | Representation |
---|---|
bin | 11101110111000111100001… |
… | …110101111001100111101010 |
3 | 122020000010021110212210100000 |
4 | 131313013201311321213222 |
5 | 114203211344011404114 |
6 | 1143152344053123430 |
7 | 36443231465145540 |
oct | 3567074165714752 |
9 | 566003243783300 |
10 | 131331004013034 |
11 | 38934190a78291 |
12 | 128909b3629576 |
13 | 58385caa58367 |
14 | 2460651265d90 |
15 | 102b34a31ce09 |
hex | 7771e1d799ea |
131331004013034 has 96 divisors (see below), whose sum is σ = 337341461184000. Its totient is φ = 37512416641392.
The previous prime is 131331004013023. The next prime is 131331004013087. The reversal of 131331004013034 is 430310400133131.
131331004013034 is a `hidden beast` number, since 1 + 3 + 1 + 3 + 310 + 0 + 40 + 1 + 303 + 4 = 666.
It is a super-2 number, since 2×1313310040130342 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a junction number, because it is equal to n+sod(n) for n = 131331004012989 and 131331004013007.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 6387157 + ... + 17420039.
It is an arithmetic number, because the mean of its divisors is an integer number (3513973554000).
Almost surely, 2131331004013034 is an apocalyptic number.
131331004013034 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is a practical number, because each smaller number is the sum of distinct divisors of 131331004013034, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (168670730592000).
131331004013034 is an abundant number, since it is smaller than the sum of its proper divisors (206010457170966).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131331004013034 is a wasteful number, since it uses less digits than its factorization.
131331004013034 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11036406 (or 11036394 counting only the distinct ones).
The product of its (nonzero) digits is 3888, while the sum is 27.
Adding to 131331004013034 its reverse (430310400133131), we get a palindrome (561641404146165).
The spelling of 131331004013034 in words is "one hundred thirty-one trillion, three hundred thirty-one billion, four million, thirteen thousand, thirty-four".
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