Base | Representation |
---|---|
bin | 100111001000111… |
… | …1000011100011011 |
3 | 10101112020002022022 |
4 | 1032101320130123 |
5 | 10142201413431 |
6 | 334152445055 |
7 | 44354645363 |
oct | 11621703433 |
9 | 3345202268 |
10 | 1313310491 |
11 | 614369679 |
12 | 3079a978b |
13 | 17c1185cc |
14 | c65c79a3 |
15 | 7a46e07b |
hex | 4e47871b |
1313310491 has 2 divisors, whose sum is σ = 1313310492. Its totient is φ = 1313310490.
The previous prime is 1313310487. The next prime is 1313310527. The reversal of 1313310491 is 1940133131.
It is a weak prime.
It is an emirp because it is prime and its reverse (1940133131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1313310491 - 22 = 1313310487 is a prime.
It is a super-3 number, since 3×13133104913 (a number of 28 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 1313310491.
It is not a weakly prime, because it can be changed into another prime (1313310991) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656655245 + 656655246.
It is an arithmetic number, because the mean of its divisors is an integer number (656655246).
Almost surely, 21313310491 is an apocalyptic number.
1313310491 is a deficient number, since it is larger than the sum of its proper divisors (1).
1313310491 is an equidigital number, since it uses as much as digits as its factorization.
1313310491 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 972, while the sum is 26.
The square root of 1313310491 is about 36239.6259776505. The cubic root of 1313310491 is about 1095.1051075408.
The spelling of 1313310491 in words is "one billion, three hundred thirteen million, three hundred ten thousand, four hundred ninety-one".
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