Base | Representation |
---|---|
bin | 1011111100011100110101… |
… | …0011100101101110010011 |
3 | 1201111111222110120102012022 |
4 | 2333013031103211232103 |
5 | 3210133202312112103 |
6 | 43533142402322055 |
7 | 2523560635520243 |
oct | 277071523455623 |
9 | 51444873512168 |
10 | 13133159488403 |
11 | 4203818172269 |
12 | 158136465932b |
13 | 7435b42b60c6 |
14 | 335910d71b23 |
15 | 17b954a95138 |
hex | bf1cd4e5b93 |
13133159488403 has 2 divisors, whose sum is σ = 13133159488404. Its totient is φ = 13133159488402.
The previous prime is 13133159488331. The next prime is 13133159488411. The reversal of 13133159488403 is 30488495133131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13133159488403 - 212 = 13133159484307 is a prime.
It is not a weakly prime, because it can be changed into another prime (13133159488103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566579744201 + 6566579744202.
It is an arithmetic number, because the mean of its divisors is an integer number (6566579744202).
Almost surely, 213133159488403 is an apocalyptic number.
13133159488403 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133159488403 is an equidigital number, since it uses as much as digits as its factorization.
13133159488403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3732480, while the sum is 53.
The spelling of 13133159488403 in words is "thirteen trillion, one hundred thirty-three billion, one hundred fifty-nine million, four hundred eighty-eight thousand, four hundred three".
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