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13133159488403 is a prime number
BaseRepresentation
bin1011111100011100110101…
…0011100101101110010011
31201111111222110120102012022
42333013031103211232103
53210133202312112103
643533142402322055
72523560635520243
oct277071523455623
951444873512168
1013133159488403
114203818172269
12158136465932b
137435b42b60c6
14335910d71b23
1517b954a95138
hexbf1cd4e5b93

13133159488403 has 2 divisors, whose sum is σ = 13133159488404. Its totient is φ = 13133159488402.

The previous prime is 13133159488331. The next prime is 13133159488411. The reversal of 13133159488403 is 30488495133131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13133159488403 - 212 = 13133159484307 is a prime.

It is not a weakly prime, because it can be changed into another prime (13133159488103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566579744201 + 6566579744202.

It is an arithmetic number, because the mean of its divisors is an integer number (6566579744202).

Almost surely, 213133159488403 is an apocalyptic number.

13133159488403 is a deficient number, since it is larger than the sum of its proper divisors (1).

13133159488403 is an equidigital number, since it uses as much as digits as its factorization.

13133159488403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3732480, while the sum is 53.

The spelling of 13133159488403 in words is "thirteen trillion, one hundred thirty-three billion, one hundred fifty-nine million, four hundred eighty-eight thousand, four hundred three".