Base | Representation |
---|---|
bin | 11000011101100110… |
… | …01110101010001111 |
3 | 1020220021110022101111 |
4 | 30032303032222033 |
5 | 203344100243203 |
6 | 10011110152451 |
7 | 643311314461 |
oct | 141663165217 |
9 | 36807408344 |
10 | 13133212303 |
11 | 562a3a0872 |
12 | 2666352727 |
13 | 1313b73653 |
14 | 8c8324131 |
15 | 51ceb726d |
hex | 30eccea8f |
13133212303 has 4 divisors (see below), whose sum is σ = 13412642400. Its totient is φ = 12853782208.
The previous prime is 13133212297. The next prime is 13133212331. The reversal of 13133212303 is 30321233131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30321233131 = 7 ⋅4331604733.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13133212303 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13133212003) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 139714978 + ... + 139715071.
It is an arithmetic number, because the mean of its divisors is an integer number (3353160600).
Almost surely, 213133212303 is an apocalyptic number.
13133212303 is a deficient number, since it is larger than the sum of its proper divisors (279430097).
13133212303 is an equidigital number, since it uses as much as digits as its factorization.
13133212303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 279430096.
The product of its (nonzero) digits is 972, while the sum is 22.
Adding to 13133212303 its reverse (30321233131), we get a palindrome (43454445434).
The spelling of 13133212303 in words is "thirteen billion, one hundred thirty-three million, two hundred twelve thousand, three hundred three".
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