131332524034540 has 24 divisors (see below), whose sum is σ = 275949588700800. Its totient is φ = 52504192808448.

The previous prime is 131332524034493. The next prime is 131332524034549. The reversal of 131332524034540 is 45430425233131.

131332524034540 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a super-2 number, since 2×131332524034540² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131332524034493 and 131332524034502.

It is not an unprimeable number, because it can be changed into a prime (131332524034549) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1801012965 + ... + 1801085884.

It is an arithmetic number, because the mean of its divisors is an integer number (11497899529200).

Almost surely, 2^{131332524034540} is an apocalyptic number.

131332524034540 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131332524034540 is an abundant number, since it is smaller than the sum of its proper divisors (144617064666260).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131332524034540 is a wasteful number, since it uses less digits than its factorization.

131332524034540 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3602100681 (or 3602100679 counting only the distinct ones).

The product of its (nonzero) digits is 518400, while the sum is 40.

Adding to 131332524034540 its reverse (45430425233131), we get a palindrome (176762949267671).

The spelling of 131332524034540 in words is "one hundred thirty-one trillion, three hundred thirty-two billion, five hundred twenty-four million, thirty-four thousand, five hundred forty".