Base | Representation |
---|---|
bin | 111101001010000001… |
… | …1101100111000001011 |
3 | 110112222211020112022111 |
4 | 1322110003230320023 |
5 | 4122432223021344 |
6 | 140200014203151 |
7 | 12326361140404 |
oct | 1722403547013 |
9 | 415884215274 |
10 | 131333017099 |
11 | 50775078659 |
12 | 215531b34b7 |
13 | c5000ccb4b |
14 | 64dc5429ab |
15 | 3639dc6834 |
hex | 1e940ece0b |
131333017099 has 2 divisors, whose sum is σ = 131333017100. Its totient is φ = 131333017098.
The previous prime is 131333017063. The next prime is 131333017139. The reversal of 131333017099 is 990710333131.
It is an a-pointer prime, because the next prime (131333017139) can be obtained adding 131333017099 to its sum of digits (40).
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131333017099 - 213 = 131333008907 is a prime.
It is a super-2 number, since 2×1313330170992 (a number of 23 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (131333017399) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65666508549 + 65666508550.
It is an arithmetic number, because the mean of its divisors is an integer number (65666508550).
Almost surely, 2131333017099 is an apocalyptic number.
131333017099 is a deficient number, since it is larger than the sum of its proper divisors (1).
131333017099 is an equidigital number, since it uses as much as digits as its factorization.
131333017099 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 45927, while the sum is 40.
The spelling of 131333017099 in words is "one hundred thirty-one billion, three hundred thirty-three million, seventeen thousand, ninety-nine".
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