13133310131111 has 2 divisors, whose sum is σ = 13133310131112. Its totient is φ = 13133310131110.

The previous prime is 13133310131083. The next prime is 13133310131159. The reversal of 13133310131111 is 11113101333131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13133310131111 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13133310131411) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566655065555 + 6566655065556.

It is an arithmetic number, because the mean of its divisors is an integer number (6566655065556).

Almost surely, 2^{13133310131111} is an apocalyptic number.

13133310131111 is a deficient number, since it is larger than the sum of its proper divisors (1).

13133310131111 is an equidigital number, since it uses as much as digits as its factorization.

13133310131111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 243, while the sum is 23.

Adding to 13133310131111 its reverse (11113101333131), we get a palindrome (24246411464242).

The spelling of 13133310131111 in words is "thirteen trillion, one hundred thirty-three billion, three hundred ten million, one hundred thirty-one thousand, one hundred eleven".