1313331110081 has 2 divisors, whose sum is σ = 1313331110082. Its totient is φ = 1313331110080.

The previous prime is 1313331109949. The next prime is 1313331110083. The reversal of 1313331110081 is 1800111333131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1310509800625 + 2821309456 = 1144775^2 + 53116^2 .

It is an emirp because it is prime and its reverse (1800111333131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1313331110081 - 2²² = 1313326915777 is a prime.

It is a super-2 number, since 2×1313331110081² (a number of 25 digits) contains 22 as substring.

Together with 1313331110083, it forms a pair of twin primes.

It is a Chen prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1313331110081.

It is not a weakly prime, because it can be changed into another prime (1313331110083) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 656665555040 + 656665555041.

It is an arithmetic number, because the mean of its divisors is an integer number (656665555041).

Almost surely, 2^{1313331110081} is an apocalyptic number.

It is an amenable number.

1313331110081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1313331110081 is an equidigital number, since it uses as much as digits as its factorization.

1313331110081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 26.

The spelling of 1313331110081 in words is "one trillion, three hundred thirteen billion, three hundred thirty-one million, one hundred ten thousand, eighty-one".