Base | Representation |
---|---|
bin | 1011111100011101011110… |
… | …1010010111100110001101 |
3 | 1201111112102120111111121211 |
4 | 2333013113222113212031 |
5 | 3210134031301411023 |
6 | 43533211530254421 |
7 | 2523565145360341 |
oct | 277072752274615 |
9 | 51445376444554 |
10 | 13133333232013 |
11 | 42038a7251425 |
12 | 15813b2887411 |
13 | 7436112a9387 |
14 | 33592a07b621 |
15 | 17b964e64a0d |
hex | bf1d7a9798d |
13133333232013 has 2 divisors, whose sum is σ = 13133333232014. Its totient is φ = 13133333232012.
The previous prime is 13133333231987. The next prime is 13133333232049. The reversal of 13133333232013 is 31023233333131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10232180693284 + 2901152538729 = 3198778^2 + 1703277^2 .
It is a cyclic number.
It is not a de Polignac number, because 13133333232013 - 225 = 13133299677581 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13133333232053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6566666616006 + 6566666616007.
It is an arithmetic number, because the mean of its divisors is an integer number (6566666616007).
Almost surely, 213133333232013 is an apocalyptic number.
It is an amenable number.
13133333232013 is a deficient number, since it is larger than the sum of its proper divisors (1).
13133333232013 is an equidigital number, since it uses as much as digits as its factorization.
13133333232013 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 26244, while the sum is 31.
Adding to 13133333232013 its reverse (31023233333131), we get a palindrome (44156566565144).
The spelling of 13133333232013 in words is "thirteen trillion, one hundred thirty-three billion, three hundred thirty-three million, two hundred thirty-two thousand, thirteen".
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