Base | Representation |
---|---|
bin | 11101110111001010011010… |
… | …011101100011100111111111 |
3 | 122020000102021100012012000221 |
4 | 131313022122131203213333 |
5 | 114203234214430311242 |
6 | 1143154015301202211 |
7 | 36443401315510306 |
oct | 3567123235434777 |
9 | 566012240165027 |
10 | 131334101416447 |
11 | 38935530416316 |
12 | 12891518a00367 |
13 | 58389a2684547 |
14 | 246086678543d |
15 | 102b47c202167 |
hex | 77729a7639ff |
131334101416447 has 2 divisors, whose sum is σ = 131334101416448. Its totient is φ = 131334101416446.
The previous prime is 131334101416409. The next prime is 131334101416459. The reversal of 131334101416447 is 744614101433131.
It is a strong prime.
It is an emirp because it is prime and its reverse (744614101433131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131334101416447 - 231 = 131331953932799 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131334101416747) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (31) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65667050708223 + 65667050708224.
It is an arithmetic number, because the mean of its divisors is an integer number (65667050708224).
Almost surely, 2131334101416447 is an apocalyptic number.
131334101416447 is a deficient number, since it is larger than the sum of its proper divisors (1).
131334101416447 is an equidigital number, since it uses as much as digits as its factorization.
131334101416447 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 290304, while the sum is 43.
Adding to 131334101416447 its reverse (744614101433131), we get a palindrome (875948202849578).
The spelling of 131334101416447 in words is "one hundred thirty-one trillion, three hundred thirty-four billion, one hundred one million, four hundred sixteen thousand, four hundred forty-seven".
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