Base | Representation |
---|---|
bin | 111101001010000100… |
… | …0011000110010001001 |
3 | 110112222220112221101022 |
4 | 1322110020120302021 |
5 | 4122433031324023 |
6 | 140200100402225 |
7 | 12326404444652 |
oct | 1722410306211 |
9 | 415886487338 |
10 | 131334245513 |
11 | 50775837579 |
12 | 215536a6375 |
13 | c500440013 |
14 | 64dc782529 |
15 | 363a06a7c8 |
hex | 1e94218c89 |
131334245513 has 2 divisors, whose sum is σ = 131334245514. Its totient is φ = 131334245512.
The previous prime is 131334245507. The next prime is 131334245519. The reversal of 131334245513 is 315542433131.
It is a balanced prime because it is at equal distance from previous prime (131334245507) and next prime (131334245519).
It can be written as a sum of positive squares in only one way, i.e., 77002365049 + 54331880464 = 277493^2 + 233092^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131334245513 is a prime.
It is not a weakly prime, because it can be changed into another prime (131334245519) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65667122756 + 65667122757.
It is an arithmetic number, because the mean of its divisors is an integer number (65667122757).
Almost surely, 2131334245513 is an apocalyptic number.
It is an amenable number.
131334245513 is a deficient number, since it is larger than the sum of its proper divisors (1).
131334245513 is an equidigital number, since it uses as much as digits as its factorization.
131334245513 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 64800, while the sum is 35.
Adding to 131334245513 its reverse (315542433131), we get a palindrome (446876678644).
The spelling of 131334245513 in words is "one hundred thirty-one billion, three hundred thirty-four million, two hundred forty-five thousand, five hundred thirteen".
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